(12x^2+9x-7)/3x

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Solution for (12x^2+9x-7)/3x equation:


x in (-oo:+oo)

x*((12*x^2+9*x-7)/3) = 0

(x*(12*x^2+9*x-7))/3 = 0

12*x^2+9*x-7 = 0

12*x^2+9*x-7 = 0

DELTA = 9^2-(-7*4*12)

DELTA = 417

DELTA > 0

x = (417^(1/2)-9)/(2*12) or x = (-417^(1/2)-9)/(2*12)

x = (417^(1/2)-9)/24 or x = (-(417^(1/2)+9))/24

(x+(417^(1/2)+9)/24)*(x-((417^(1/2)-9)/24)) = 0

(x*(x+(417^(1/2)+9)/24)*(x-((417^(1/2)-9)/24)))/3 = 0

( x+(417^(1/2)+9)/24 )

x+(417^(1/2)+9)/24 = 0 // - (417^(1/2)+9)/24

x = -((417^(1/2)+9)/24)

( x-((417^(1/2)-9)/24) )

x-((417^(1/2)-9)/24) = 0 // + (417^(1/2)-9)/24

x = (417^(1/2)-9)/24

( x )

x = 0

x in { -((417^(1/2)+9)/24), (417^(1/2)-9)/24, 0 }

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